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3xx10^(-3) kg acetic acid is added into ...

`3xx10^(-3)` kg acetic acid is added into `500 cm^(3)` water. If dissociation of acetic acid is 23% then find out depression in freezing ? `K_(f)` of water = 1.86 K kg / mol and density = 0.997 gm `cm^(-3)`.

Text Solution

Verified by Experts

The correct Answer is:
`0.23k`
`DeltaT = K_(f) xx` molality `xx (1-alpha)`
For acetic acid: `{:(CH_(3)COOH hArr,CH_(3)COOH+,H^(+)),(1,0,0),(1-alpha,alpha,alpha):}`
Given, `alpha = 0.23`, Also molality
`=("mole of acetic acid")/("weight of water in kg")`
`=(3 xx 10^(-3) xx 10^(-3))/(60xx(500 xx 0.997)/(10^(3))) = 0.10`
`DeltaT = K_(f) xx` molality `(1-alpha)`
`DeltaT = 1.86 xx 0.1 xx 1.23 = 0.229`
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