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1.5g of monobasic acid when dissolved in...

`1.5g` of monobasic acid when dissolved in `150g` of water lowers the freezing point by `0.165^(@)C.0.5g` of the same acid when titrated, after dissolution in water, requires `37.5 mL` of `N//10` alkali. Calculate the degree of dissociation of the acid `(K_(f)` for water `= 1.86^(@)C mol^(-1))`.

Text Solution

Verified by Experts

The correct Answer is:
`18.27%`
`(0.5)/(M) = 3.75 xx 10^(-3) rArr M = 133.33`
`0.165 = (1-alpha) xx (1.86 xx 1.5 xx 1000)/(133.33 xx 150)`
`1 + alpha =1.1827`
`alpha = 0.1827 = 18.27%`
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