Home
Class 12
CHEMISTRY
30mL of CH(3)OH (d = 0.780 g cm^(-3)) an...

`30mL` of `CH_(3)OH (d = 0.780 g cm^(-3))` and `70 mL` of `H_(2)O (d = 0.9984 g cm^(-3))` are mixed at `25^(@)C` to form a solution of density `0.9575 g cm^(-3)`. Calculate the freezing point of the solution. `K_(f)(H_(2)O)` is `1.86 kg mol^(-1)K`. Also calculate its molarity.

Text Solution

Verified by Experts

The correct Answer is:
`-19.91^(@)C, 7.63M`

`CH_(3) OH rarr V_(1) = 30 mL, d_(1) = 0.798 g//mL`
`m_(1) = 23.94 g`
`H_(2)O rarr V_(2) = 70 mL, d_(2) = 0.9984 g//mL`
`m_(2) = 69.888g`
`m_(T) = 93.828g`
`d_("solution") = 0.9575 g//mL`
`V_("solution") = 98 mL`
`DeltaT_(f) = (1.86 xx 23.94 xx 1000)/(32xx 69.888) = 19.91`
`T_(f) =- 19.91^(@)C`
`M = (23.94)/(32 xx 0.98) = 7.63M`
Promotional Banner

Similar Questions

Explore conceptually related problems

The freezing poing of an aqueous solution of a non-electrolyte is -0.14^(@)C . The molarity of this solution is [K_(f) (H_(2)O) = 1.86 kg mol^(-1)] :

3.0 molal NaOH solution has a density of 1.110 g//mL . The molarity of the solution is:

Addition of 0.643g of a compound to 50mL of benzene (density: 0.879g mL^(-1)) lower the freezing point from 5.51^(@)C to 5.03^(@)C . If K_(f) for benzene is 5.12 K kg mol^(-1) , calculate the molar mass of the compound.

1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% ionized. The boiling point of the solution is (K_(b) for H_(2)O = 0.52 K kg//mol) :

If 20 mL of ethanol (density =0.7893g//mL) is mixed with 40mL water (density = 0.9971g//mL) at 25^(@)C , the final slution has density of 0.9571g//mL . Calculate the percentage change in total volume of mixing. Also calculate the molarity of alcohol in the final solution.