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In a 0.2 molal aqueous solution of a wea...

In a `0.2` molal aqueous solution of a weak acid `HX` the degree of ionization is `0.3`. Taking `k_(f)` for water as `1.85` the freezing point of the solution will be nearest to-

A

`-260^(@)C`

B

`+0.480^(@)C`

C

`-0.480^(@)C`

D

`-0.360^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
`T'_(f) = T_(f) - iK_(f)m`
`=0^(@)C -(1+0.3) xx 1.85 xx 0.2 =- 0.481^(@)C`
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