`18g` of glucose `(C_(6)H_(12)O_(6))` is added to `178.2g` of water. The vapour pressure of water for this aqueous solution at `100^(@)C` is-

Options

A. `7.60` Torr
B. `76.00` Torr
C. `752.40` Torr
D. `759.00` Torr

Answer

C

Explanation

`PA = P_(A)^(@) x_(A) = 760 xx (178.2//18)/((178.2)/(18)+(18)/(180))`
`= 760 xx (9.9)/(10) = 752.4` torr