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The degree of dissociation (alpha) of a ...

The degree of dissociation `(alpha)` of a weak electrolyte, `A_(x)B_(y)` is related to van't Hoff's factor `(i)` by the expression:

A

`alpha = (x+y -1)/(i-1)`

B

`alpha = (x+y +1)/(i-1)`

C

`alpha = (i-1)/((x+y-1))`

D

`alpha =(i-1)/(x+y+1)`

Text Solution

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The correct Answer is:
C
`{:(AxByrarr,xA^(y+)+,yB^(x-),i=(1-prop+xprop +y prop)),(|,,-,-),(1-prop,xprop,yprop,prop=(i-1)/(x+y-1)):}`
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