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K(f) for waer is 1.86 K kg mol^(-1). If ...

`K_(f)` for waer is `1.86 K kg mol^(-1)`. If your automobile radiator holds `1.0 kg` of water, how many grams of ethylene glycol `(C_(2)H_(6)O_(2))` must you add to get the freezing point of the solution lowered to `-2.8^(@)C`?

A

`27g`

B

`72g`

C

`93g`

D

`39g`

Text Solution

Verified by Experts

The correct Answer is:
C
`2.8 = 1.86 xx (w//62)/(1) rArr w = 93.33gm`
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