The solution of 6.8 gram non-ionic substance in 100 ram water is freezed at `- 0.93^(@)C`. What is the molar mass of unknown substance ? `(K_(f)=1.86)`

Options

A. `0.875 M`
B. `1.00M`
C. `1.75M`
D. `0.975M`

Answer

A

Explanation

`M_("resultant") = (M_(1)V_(1)+M_(2)V_(2))/(V_("total"))`
`= (0.5 xx 750 + 2xx 250)/(1000)`
`= (375 +500)/(1000) = 0.875M`