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Malachite on calcination gives rarr 'A' ...

Malachite on calcination gives `rarr 'A' + CO_(2) +H_(2)O`. Compound 'A' on reduction with carbon gives `rarr CO +'B'` Here 'A' and 'B' are

A

`Fe_(2)O_(3), Fe`

B

`CuO, Cu`

C

`CuCO_(3),CuO`

D

`MgO, Mg`

Text Solution

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The correct Answer is:
B
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