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A water drop of radius 1 mm is broken in...

A water drop of radius 1 mm is broken into `10^(6)` identical drops, surface tension of water is 72 dynes/cm find the energy spent in this process.

Text Solution

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As volume of water remains constant, so `(4)/(3)piR^(3)=n(4)/(3)pir^(3)impliesr=(R)/(n^(1//3))`
Increase in surface area `DeltaA=n(4pir^(2))-4piR^(2)=4pi(n^(1//3)-1)R^(2)=4pi(100-1)10^(-6)`
`therefore` Energy spent `=TDeltaA=4pixx99xx10^(-6)xx72xx10^(-3)=89.5xx10^(-6)J`
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