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A bob of mass m suspended by a light str...

A bob of mass m suspended by a light string of length L is whirled into a vertical circle as shown figure . What will be the trajectory of the particle , if the string is cut at
(a) point B ? (b) point C ? (C ) Point X ?

Text Solution

Verified by Experts

The correct Answer is:
D
`OA=2cos30^(@)-sqrt(3)mimpliesAB=vt=sqrt((4.96))/(sqrt(5))sthereforeOB=3.95m`
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