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Two particles of masses 1.0 kg and 2.0 k...

Two particles of masses 1.0 kg and 2.0 kg are placed at a separation of 50 cm. Assuming that the only forces acting on the particles are their mutual gravitation find the initial acceleration of the two particles.

Text Solution

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Force exerted by one particle on another `F=(Gm_(1)m_(2))/(r^(2))=(6.67xx10^(-11)xx1xx2)/((0.5)^(2))=5.34xx10^(-10)N`
Acceleration of heavier particle `=(f)/(m^(2))=(5.3xx10^(-10))/(2)=2.67xx10^(-10)ms^(-2)`
This example shows that gravitation is verty weak but only this force keep bind our solar system and also this universe of all galaxies and other interstellar system.
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