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Two particles of equal mass (m) each mov...


Two particles of equal mass (m) each move in a circle of radius (r) under the action of their mutual gravitational attraction find the speed of each particle.

A

`(1)/(2R)sqrt((1)/(Gm))`

B

`sqrt((Gm)/(2R))`

C

`(1)/(2)sqrt((Gm)/(R))`

D

`sqrt((4Gm)/(R))`

Text Solution

Verified by Experts

The correct Answer is:
C
Centripetal force provided by the gravitaional force of attraction
Between two particles i.e., `(mv^(2))/(R)=(Gmxxm)/((2R)^(2))impliesv=(1)/(2)sqrt((Gm)/(R))`
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