A planet in a distant solar systyem is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is `11kms^(-1)`, the escape velocity from the surface of the planet would be

Options

A. `1.1kms^(-1)`
B. `11kms^(-1)`
C. `110kms^(-1)`
D. `0.11kms^(-1)`

Answer

C

Explanation

`v_(e)=sqrt((GM)/(R))v_(e)propsqrt((M)/(R))`
`(v_(e))/(v_(e)^(1))=sqrt((M_(e))/(R_(e))xx(R_(p))/(M_(p)))impliessqrt((M_(e))/(R_(e))xx(R_(e)//10)/(10Me))`
`(11)/(v_(e)^(1))=(1)/(10),v_(e)^(1)=110m//s`