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Two beams of light havin intensities I a...

Two beams of light havin intensities I and 4I interferer to produce a fringe pattern on a screen. The phase difference between the beam is`(pi)/(2)` at point A and `2pi` at point B. then find out the difference between the resultant intensities at A and B.

Text Solution

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Resultant intensity `I=I_(1)+I_(2)+2sqrt(I_(1))sqrt(I_(1))cosphi`
Resultant intensity at point A is `I_(A)=I+4I+2sqrt(I)sqrt(4I)cos((pI)/(2))=5I`
Resultant intensity at point `B,I_(B)=I+4I+2sqrt(I)sqrt(4I)cos2pi=9I(becausecos2pi=1)thereforeI_(B)-I_(A)=91-51implies41`
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