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In the Young's double slit experiment, t...

In the Young's double slit experiment, the intensity of light at a point on the screen where the path difference is `lambda` is K. (K being the wavelength of light used). The intensity at 2 a point where the path difference is `(lambda)/(4)` will be.....

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`phi_(1)=(2pidelta)/(lamda)implies(2pi)/(lamda)xxlamda=2pi`
and `phi_(2)=(2pi)/(lamda)xx(lamda)/(4)=(pi)/(2)I_(1)=I_(0)+I_(0)+2sqrt(I_(0))sqrt(I_(0))cos2pi=4I_(0)`
and `I_(2)=I_(0)+I_(0)+2sqrt(I_(0))sqrt((I_(0))(cos2pi)/(2))=2I_(0)`
`therefore(I_(1))/(I_(2))=(4I_(0))/(2I_(0))=2impliesI_(2)=(I_(1))/(2)=(K)/(2)` unit `[becauseI_(1)=K"unit"`]
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