In fresnel's biprism experiment the distance between the source and the screen is 1 m and that between the source and biprism is 10 cm. the wavelength of light used is 6000Å. The fringe width obtained is 0.03 cm and the refracting angle of biprism is `1^(@)` then calculate the refractive index of the material of biprism.

Explanation

`beta=(Dlamda)/(2a(mu-1)alpha)therefore(mu-1)=(Dlamda)/(2abeta(alpha))=(1xx6xx10^(-7)xx180)/(2xx0.1xx3xx10^(-4)xx3.14)implies(mu-1)=0.573impliesmu=1.573`