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A micture of light, consisting of wavelength 600nm and an unknown wavelength, illuminates Young's double slit and gives rise to two overlapping interference patterns on the scree. The central maximum of both lights coincide. Further, it is obseved that the third bright fringe of known light coincides with the 4th bright fringe of the unknown light. From this data, the wavelength of the unknown light is:

A

450 nm

B

776.8 nm

C

393.4 nm

D

885.0 nm

Text Solution

Verified by Experts

The correct Answer is:
A

third bright of known light
`X_(3)=(3lamda_(1)D)/(d)` .(1)
`4^(th)` brigt of unknown light
`X_(4)=(4lamda_(2)D)/(d)` ..(2)
Given `X_(3)=X_(4)`
`3lamda_(1)=4lamda_(2)`
`lamda_(2)=(3)/(4)lamda_(1)=(3)/(4)xx590=442.5nm`
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ALLEN -WAVE OPTICS-Exercise 5 A (Previous Years Questions)
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  2. The maximum number of possible interference maxima for slit-separation...

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  3. A Young's double slit experiment uses a monochromatic source. The shap...

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  4. In a Young's double slit experiment the intensity at a point where tha...

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  8. An intially parallel cyclindrical beam travels in a medium of refracti...

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  14. Two beams A and B, of plane polarized light with mutually perpendicula...

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  16. In a Young's double slit experiment with light of wavelength lamda the...

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