In Young's double slit experiment, one of the slit is wider than other, so that the amplitude of the light from one slit is double of that from other slit. If `I_(m)` be the maximum intensity the resultant intensity I when they interface at phase difference `phi` is given by .......

Options

A. `(I_(m))/(9)(1+8cos^(2)((phi)/(2)))`
B. `(I_(m))/(9)(4+5cosphi)`
C. `(I_(m))/(3)(1+2cos^(2)((phi)/(2)))`
D. `(I_(m))/(5)(1+4cos^(2)((phi)/(2)))`

Answer

A

Explanation

For bright fringe `S_(1)P-S_(2)P=nlamda`
So fringes are concentric circles (centre of origin)