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A progressive wave on a string having li...

A progressive wave on a string having linear mass density `rho` is represented by `y=A sin((2 pi)/(lamda)x-omegat)` where `y` is in mm. Find the total energy (in `mu J`) passing through origin from `t=0` to `t=(pi)/(2 omega)`.
[Take : `rho = 3 xx 10^(-2) kg//m , A = 1mm , omega = 100 rad..sec , lamda = 16 cm`].

A

6

B

7

C

8

D

9

Text Solution

Verified by Experts

The correct Answer is:
A
Total energy `(1)/(2) rho A^(2) omega^(2)xx(lamda)/(4)`.
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