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A standing wave is created on a string ...

A standing wave is created on a string of length `120 m` and it is vibrating in `6 th` harmonic. Maximum possible amplitude of any particle is `10 cm` and maximum possible velocity will be `10 cm//s`. Choose the correct statement.

A

Angular wave number of two waves will be `(pi)/(20)`

B

Time period of any particle's `SHM` will be `4 pi sec`.

C

Any particle will have same kinetic energy as potential energy

D

Amplitude of interfering waves are `10 cm` each.

Text Solution

Verified by Experts

The correct Answer is:
A
`6((lamda)/(2))=120 rArr lamda =40 rArr k=(pi)/(20) rArr Aomega = v_(max) rArr omega = 1 rArr T=2pi`.
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