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A man generates a symmetrical pulse in a...

A man generates a symmetrical pulse in a string by moving his hand up and down. At `t=0` the point in his hand moves downward. The pulse travels with speed of `3 m//s` on the string & his hands passes `6` times in each second from the mean position. Then the point on the string at a distance `3m` will reach its upper extreme first time at time `t=`

A

`1.25 sec`

B

1 sec

C

`(11)/(12) sec`

D

none

Text Solution

Verified by Experts

The correct Answer is:
A
Frequency of wave `= (6)/(2)-3 rArr T=(1)/(3) s, lamda -vT=(3)((1)/(3))=1m`
Total time taken `= (3)/(3)+(3T)/(4)=1.25 sec`.
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ALLEN -WAVES AND OSCILLATIONS-Part-1(Exercise-05)[B]
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