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A progressive wave having amplitude 5 m ...

A progressive wave having amplitude `5 m` and wavelength `3m`. If the maximum average velocity of particle in half time period is `5 m//s` and waves is moving in the positive x-direction then find which may be the correct equation (s) of the wave ? [wave `x` in meter].

A

`5 sin ((2pi)/(5)t-(2pi)/(3)x)`

B

`4 sin((pit)/(2)-(2pi)/(3))+3 cos ((pi t)/(2)-(2pi)/(3)x)`

C

`5 sin ((pi t)/(2)-(2pi)/(3)x)`

D

`3 cos((2pi)/(5)t-(2pi)/(3)x)-4 sin ((2pi)/(5)t-(2pi)/(3)x)`

Text Solution

Verified by Experts

The correct Answer is:
B, C

`because lamda = 3 m :. k=(2pi)/(lamda)=(2pi)/(3)`
Maximum displacement in half time period `= 2a = 10 m`
So maximum average velocity `(10)/(.^(T)//_(2))=5 rArr T=4s rArr omega = (2pi)/(T)=(2pi)/(4)=(pi)/(2)`.
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