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A uniform string of length 20m is suspen...

A uniform string of length `20m` is suspended from a rigid support. A short wave pulse is introduced at its lowest end. It starts moving up the string. The time taken to reach the support is :
(take `g = 10ms^(-2)`)

A

`sqrt(2) s`

B

`2 pi sqrt(2) s`

C

`2 s`

D

`2 sqrt(2) s`

Text Solution

Verified by Experts

The correct Answer is:
D
Velocity at point `p=sqrt(((m)/(L)gx)/(m//L))`
`v = sqrt(gx)`
`(dx)/(dt)= sqrt(gx)`
`underset(0)overset(20)(int)(dx)/(sqrt(x))=underset(0)overset(t)(int)sqrt(g)dt`
`t = 2 sqrt(2)sec`
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