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The least count of a stop watch is (1)/(...

The least count of a stop watch is `(1)/(5)` second. The time of 20 oscillations of a pendulum is measured to be 25 seconds. How much will be the percentage error in the measurement of time ?

A

0.03

B

0.01

C

`0.8%`

D

0.16

Text Solution

Verified by Experts

The correct Answer is:
C
`(DeltaT)/(T)xx100=(1//5)/(25)xx100=0.8%`
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