Home
Class 11
PHYSICS
Consider S = X cos (theta) for X = (2.0 ...

Consider `S = X cos (theta)` for `X = (2.0 pm 0.2) cm, theta = 53 pm 2^(@)`. Find S.

Text Solution

Verified by Experts

The correct Answer is:
`S = (1.2 pm 0.18) cm`
`S=xcos theta=(2)cos53^(@)=(2)((3)/(5))=1.2`
`(DeltaS)/(S)=(Deltax)/(x)+(Delta(cos theta))/(cos theta)=(Deltax)/(x)+(tan theta)Delta theta rArr Delta S = 1.2`
`[(0.2)/(2)+((4)/(3))(2xx(pi)/(180))]=0.12+0.06=0.18`
`rArr S = (1.2 pm 0.18)cm`
Promotional Banner

Topper's Solved these Questions

  • ERROR AND MEASUREMENT

    ALLEN |Exercise Part-2(Exercise-2)(A)|16 Videos

  • ERROR AND MEASUREMENT

    ALLEN |Exercise Part-2(Exercise-2)(B)|22 Videos

  • ERROR AND MEASUREMENT

    ALLEN |Exercise Part-2(Exercise-2)(B)|22 Videos

  • ELASTICITY, SURFACE TENSION AND FLUID MECHANICS

    ALLEN |Exercise Exercise 5 B (Integer Type Questions)|3 Videos

  • KINEMATICS

    ALLEN |Exercise EXERCISE-2|89 Videos

Similar Questions

Explore conceptually related problems

Ab object covers (16.0 pm 0.4) m distance in (4.0 pm 0.2) s. Find out the second.

Find (dy)/(dx) : x= cos^(2) theta and y= sin^(2) theta

Consider a triangle PQR ,right at R ,in which PQ = 29 units ,QR =21 units and angle PQR =theta , then find the values of (i) cos ^(2) theta + sin ^(2) theta and (ii) cos ^(2) theta -sin ^(2) theta

If costheta + sin theta = sqrt2 cos theta , prove that cos theta - sin theta = sqrt2 sin theta .

The original length of wire is (153.7 pm 0.6) cm . It is streched to (155.3 pm 0.2) cm. Calculate the elongation in the wire with error limits.

Find (dy)/(dx) of each of the functions expressed in parametric form: x=3 cos theta-2 cos^(3) theta, y= 3 sin theta- 2 sin^(3) theta

P_1 and P_2 are the length of perpendicular from origin to the line x sec theta + y cosec theta =a and x cos theta - y sin theta = a cos 2 theta then ….... of the following is valid.

If x sin^(3)theta + y cos^(3)theta = sintheta costheta and x sin theta = y cos theta , prove that x^(2) + y^(2) = 1.

ALLEN -ERROR AND MEASUREMENT-Part-2(Exercise-1)
  1. In a vernier calliper, N divisions of vernier scale coincide with (N-1...

    Text Solution

    |

  2. A vernier callipers having 1 main scale division = 0.1 cm to have a le...

    Text Solution

    |

  3. In a vernier callipers, N divisions of the main scale coincide with N ...

    Text Solution

    |

  4. In a vernier callipers the main scale and the vernier scale are made u...

    Text Solution

    |

  5. Consider the MB shown in the diagram, let the resistance X have temper...

    Text Solution

    |

  6. For a post office box, the graph of galvanometer deflection versus (R ...

    Text Solution

    |

  7. Identify which of the following diagrams represent the internal constr...

    Text Solution

    |

  8. In a meter bridge set up, which of the following should be the propert...

    Text Solution

    |

  9. The relative error in resistivity of a material where resistance = 1...

    Text Solution

    |

  10. In the searle's experiment, after every step of loading, why should we...

    Text Solution

    |

  11. Internal micrometer is a measuring intrument used to measure internal ...

    Text Solution

    |

  12. Internal micrometer is a measuring intrument used to measure internal ...

    Text Solution

    |

  13. Internal micrometer is a measuring intrument used to measure internal ...

    Text Solution

    |

  14. In a given slide callipers 10 division of its vernier coincides with i...

    Text Solution

    |

  15. Consider a home made vernier scale as shown in the figure. In this dia...

    Text Solution

    |

  16. The pitch of a screw gauge is 1 mm and there are 50 divisions on its c...

    Text Solution

    |

  17. A short circuit occurs in a telephone cable having a resistance of 0.4...

    Text Solution

    |

  18. A glass prism of angle A = 60^(@) gives minimum angle of deviation the...

    Text Solution

    |

  19. In a given optical bench, a needle of length 10 cm is used to estimate...

    Text Solution

    |

  20. Consider S = X cos (theta) for X = (2.0 pm 0.2) cm, theta = 53 pm 2^(@...

    Text Solution

    |