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The currect voltage relation of a diode ...

The currect voltage relation of a diode is given by `1 = (e^(van v//T) -1 )mA` where the applied volied `V` is in volts and the tempetature `T` is in degree kelvin if a student make an error meassurting `+- 01 V` while measuring the current of `5 mA at 300 K` what be the error in the value of current in `mA`

A

0.5 mA

B

0.05 mA

C

0.2 mA

D

0.02 mA

Text Solution

Verified by Experts

The correct Answer is:
C

Given current `I=(e^(1000V//T)-1)mA`
`rArr I+1=e^(1000V//T)`
`dI=(1000)/(T)[e^((1000V)/(T))]dV`
`dI=(1000)/(T)[I+1]dV=(1000)/(300)[6]xx(0.01)`
`dI=0.2mA`
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