The current flowing through the zener di...

The current flowing through the zener diode in fig is-

20 mA

25 mA

15 mA

5 mA

Text Solution

Verified by Experts

The correct Answer is:

`I_(L)=(5V)/(1k Omega)=5mA`
`I=(10-5)/(500)=10mA`
`I_(1)=I-I_(L)=10mA-5mA =5mA`

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