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Forbidden energy gap of Ge is 0.75eV, ma...

Forbidden energy gap of Ge is `0.75eV`, maximum wave length of incident radiation for producing electron-hole pair in germanium semiconductor is

A

`4200 Å`

B

`16500 Å`

C

`4700 Å`

D

`4000 Å`

Text Solution

Verified by Experts

The correct Answer is:
B
`E=(12400(eV-Å))/(lamda(Å))rArrlamda=(12400)/(0.75)=16500 Å`
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ALLEN -SEMICONDUCTORS-Part-3(Exercise-2)
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  18. Which of the following relation is valid in Boolean algebra :-

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