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In the following common emitter configur...

In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be

A

10 mV

B

0.1 V

C

1.0 V

D

10 V

Text Solution

Verified by Experts

The correct Answer is:
C
`(V_(0))/(V_("in"))=beta(R_(i))/(R_("in"))rArrV_(0)=beta(R_(i))/(R_("in"))xxV_("in")=100xx(10kOmega)/(1kOmega)xx1mV=1V`
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