A particle is moving in a vertical circle with constant speed. The tension in the string when passing through two positions at angles `30^@` and `60^@` from vertical (lowest position) are `T_1` and `T_2` respectively. Then
A
`T_(1)=T_(2)`
B
`T_(1)gtT_(2)`
C
`T_(1)ltT_(2)`
D
`T_(1)geT_(2)`
Text Solution
Verified by Experts
The correct Answer is:
B
Tension `T=(mv^(2))/(r)+ mg cos theta` for `theta=30^(@) T_(1)=(mv_(1)^(2))/(r)+mg cos 30^(@)` `theta=60^(@) T_(2)=(mv_(1)^(2))/(r) mg cos 60^(@)` `v_(1)gtv_(2)` and `cos 30^(@)gtcos60^(@)` `rArrT_(1)gtT_(2)`
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