A hollow smooth uniform `A` of mass 'm' rolls without sliding on a smooth horizontal surface collides head to elastically with another stationary smooth solid sphere `B` of the same mass `m` and same radius. The ratio of kinetic energy of 'B' to that of 'A' just after the collision is - .
A
`1:1`
B
`2:3`
C
`3:2`
D
`5:2`
Text Solution
Verified by Experts
The correct Answer is:
C
After collision `K_(A)=(1)/(2)((2)/(3)mR^(2))((v_(0))/(R))^(2)=(1)/(3)mv_(0)^(2),K_(B)=(1)/(2)mv_(0)^(2)` `rArr(K_(B))/(K_(A))=((1)/(2)mv_(0)^(2))/((1)/(3)mv_(0)^(2))=(3)/(2)`
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