What should be the radius of a planet with mass equal to that of earth and escape velocity on its surface is equal to the velocity of light. Given that mass of earth is `M=6xx10^(24)kg`.
A particle is thrown with escape velocity v_(e) from the surface of earth. Calculate its velocity at height 3 R :-
What is the value of escape velocity of a body lying on the surface of earth?
Which of the following should be the wavelength of an electron if its mass is 9.1xx10^(-31)kg and its velocity is 1//10 of that of light and the value of h is 6.6252xx10^(-24) joule second?
Diameter and mass of a planet is double that earth. Then time period of a pendulum at surface of planet is how much times of time period at earth surface :-
If the magnitude acceleration of gravity on the surface of earth is g, then at height from the surface equal to the radius of earth what will be the magnitude of g?
Potential energy of a 3kg body at the surface of a planet is -54 J , then escape velocity will be :
Escape velocity for earth surface is 11 km/s. If the radius of any planet is two times the radius of the earth but average density is same that of earth, then the escape velocity at the planet will be ........
A body is projected vertically upwards from the surface of the earth with a velocity equal to half of escape velocity of the earth. If R is radius of the earth, maximum height attained by the body from the surface of the earth is
The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to gravity at the surface the planet is equal to that at the surface of the earth. If the radius of the earth is R , the radius of the planet would be .......
