Two bodies of masses 2kg and 3kg are connected by a metel wire of cross section 0.04 `mm^(2)`. Breaking stress of metel wire is 2.5 Gpa. The maximum force F that can be applied to 3kg block so that wire does not break is :
A
100N
B
150N
C
200N
D
250N
Text Solution
Verified by Experts
The correct Answer is:
D
`(T)/(A)=2.5xx10^(9)` `T=(2.5xx10^(9))A` `T=2.5xx10^(9)xx0.04xx10^(-6)=100` Then maximum acceleration of block 2kg is = `50 m//sec^(3)` F-T=ma `F=T+ma=100+3xx50=250N`
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