The position vector of car w.r.t. its starting point is given as `vecr="at" hati+bt^(2)hatj` where a and b are positive constants. find the equation of trajectory :-
Path traced by a moving particle in space is called trajectory of the particle. Shape of trajectiry is decided by the forces acting on the particle. When a coordinate system is associated with a particle motion, the curve equation in which the particle moves [y=f(x)] is called equation of trajectory. It is just giving us the relation among x and y coordinates of the particle i.e. the locus of particle. To find equation of trajectory of a particle, find first x and y coordinates of the particle as a function of time eliminate the time factor. The position vector of car w.r.t. its starting point is given as vec(r)=at hat(i)- bt^(2) hat(j) where a and b are positive constants. The locus of a particle is:-
Differentiate a^(x) w.r.t x, where a is a positive constant
The position vector of a aprticle is given as vecr=(3t^2-2t+5)hati+(3t^2)hatj . The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to
The position vector of a aprticle is given as vecr=(t^2-4t+6)hati+(t^2)hatj . The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to
The position vector of a aprticle is given as vecr=(5t^2-4t+6)hati+(t^2)hatj . The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to
The position vector of a particle is given by vecr=vecr_(0) (1-at)t, where t is the time and a as well as vecr_(0) are constant. After what time the particle retursn to the starting point?
The position vector of a aprticle is given as vecr=(t^2-t+2)hati+(3t)hatj . The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to
square ABCD is a parallelogram. The position vectors of the points A, B and Care respectively 4hati+5hatj-10hatk,2hati-3hatj+4hatk and -hati+2hatj+hatk . Find the vector equation of the line BD.
A and B are two points. The position vector of A is 6b-2a. A point P divides the line AB in the ratio 1:2. if a-b is the position vector of P, then the position vector of B is given by
If the position vector of one end of the line segment AB be 2hati+3hatj-hatk and the position vecto of its middle point be 3(hati+hatj+hatk) , then find the position vector of the other end.
