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In the circuit the rms value of voltage ...

In the circuit the rms value of voltage across the capacitor C, inductor L and resister `R_(1)` are respectively `5sqrt(5V)`, 10 V and 5V. Then the peak voltage a cross `R_(2)` is

A

7V

B

10V

C

15V

D

`5sqrt(2)V`

Text Solution

Verified by Experts

The correct Answer is:
B
`V_(C)^(2)+V_(R)^(2)=V_(L_^(2)+V_(R)^(2):`
`125+25=100+V_(R_(2))^(2)rArrV_(R_(2))=5sqrt(2V)`,
`(V_(R_(2)))_("peak")=(5sqrt(2))xxsqrt(2)`
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