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A siphon tube is discharging a liquid of...

A siphon tube is discharging a liquid of density
`900(kg)/(m^(3))` as shown in figure. `(P_(0)=1.01xx10^(5) N//m^(2))`

Pressure at point B is

A

`4.25x10^(4) N//m^(2)`

B

`6.25xx10^(4)N//m^(2)`

C

`2.50xx10^(4)N//m^(3)`

D

`2.0xx10^(5)N//m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Applying Bernoull's theorem at A and B, we
have `P_(0)+0+0=P_(B)+(1)/(2)pv^(2)+pg(1.5)`
or `P_(B)=(1.01xx10^(5))-(1)/(2)xx900xx(10)^(2)-900`
`xx10xx1.5=4.25xx10^(4) N//m^(2)uparrow`
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