Given the following reaction and equilibrium constant
`CO(g)+(1)/(2)O_(2)(g)hArrCO_(2)(g),K_(c)=1.1xx10^(11)`
So at equilibrium select the correct response from below:-

Options

A. The net driving force for the reaction will always be left to right because the equilibrium constant is very large
B. The rate of forward reaction will always be greater than the rate of the reverse reaction because the equilibrium constant is so large
C. For a reaction mixture containing equilibrium concentrations of the three components, the forward and reverse rates will both go to zero
D. All responses above are incorrect

Answer

D