Comprehension # 5
One particle of mass `1 kg` is moving along positive x-axis with velocity `3 m//s`. Another particle of mass `2 kg` is moving along y-axis with `6 m//s`. At time `t = 0, 1 kg` mass is at `(3m, 0)` and `2 kg` at `(0, 9m), x - y` plane is the horizontal plane. (Surface is smooth for question 1 and rough for question 2 and 3)
Co-ordinates of centre of mass where it will stop finally are :-

Options

A. `(2.0 m, 14.25 m)`
B. `(2.25 m, 10 m)`
C. `(3.75 m, 9 m)`
D. `(1.75 m, 12 m)`

Answer

D

Explanation

By using `s = ut + (1)/(2)at^(2)` for individual partiles
For `1^(st)` particle : `s_(x) = (3) (1.5) + (1)/(2) (2) (1.5)^(2) = 2.25 m`
For `II^(nd)` particle `= s_(y) = (6) (3) + (1)/(2)(-2)(3)^(2) = 9m`
Therefore `X_(cm) = (2.25)/(3) + 1 = 1.75 m` and `y_(cm) = (2(9))/(3) + 6 = 12m`