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Two blocks of masses m(1) and m(2) are c...

Two blocks of masses `m_(1)` and `m_(2)` are connected by a massless pulley A, slides along th esmooth sides of a rectangular wedge of mass m, which rests on a smooth horizontal plane. Find the distance covered by the wedge on the horizontal plane till the mass `m_(1)` is lowered by the vertical distance h.

Text Solution

Verified by Experts

The correct Answer is:
`((m_(2) + m_(1) cot alpha) h)/(m + m_(1) + m_(2))`
`Deltax_(cm) = 0 = (mx_(0) + m_(1) (x_(0) - h cot alpha) + m_(2) (x_(0) - h))/(m + m_(1) + m_(2))`
`rArr x_(0) = ( (m_(2) + m_(1) cot alpha))/((m + m_(1) + m_(2)))`
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