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The block of mass M moving on the frict...

The block of mass `M` moving on the frictionless horizontal surface collides with the spring constant `k` and compresses it by length `L` . The maximum momention of the block after collision is

A

`sqrtMk L`

B

`(kL^(2))/(2M)`

C

zero

D

`(ML^(2))/(k)`

Text Solution

Verified by Experts

The correct Answer is:
A
Let maximum momentum be p then
`(p^(2))/(2M) = (1)/(2) kL^(2) rArr p = L sqrt(Mk)`
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