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If components of the momentum of a body ...

If components of the momentum of a body along x and y-axis are `p_(x)=2 cos t` and `p_(y)=2 sin t`, Find out angle between momentum and force on the body.

A

`0^(@)`

B

`30^(@)`

C

`45^(@)`

D

`90^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`vec(P)(t) = A[hat(i) cos (kt) - hat(j) sin (kt)]`
`vec(F) = (dvec(p))/(dt) = Ak [- hat(i) sin (kt) - hat(j) cos (kt)]`
`vec(F).vec(p) = Fp cos theta` But`vec(F).vec(p) = 0 rArr cos theta = 0 rArr theta = 90^(@)`
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