Home
Class 11
PHYSICS
A ball is projected with speed u at an a...

A ball is projected with speed u at an angle `theta` to the horizontal. The range R of the projectile is given by
`R=(u^(2) sin 2theta)/(g)`
for which value of `theta` will the range be maximum for a given speed of projection? (Here g= constant)

A

`pi/2 rad`

B

`pi/4 rad`

C

`pi/3 rad`

D

`pi/6 rad`

Text Solution

Verified by Experts

The correct Answer is:
B
As `sin2theta le 1` so range will be maximum if `sin 2theta=1`. Therefore `2theta=pi/2 rArr theta=pi/4 rad`
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS

    ALLEN |Exercise Part -II Example|61 Videos

  • MISCELLANEOUS

    ALLEN |Exercise Part -II Example Some worked out Examples|1 Videos

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN |Exercise BEGINNER S BOX-7|8 Videos

  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN |Exercise EXERCISE-IV|7 Videos

Similar Questions

Explore conceptually related problems

A body of mass m is projected with intial speed u at an angle theta with the horizontal. The change in momentum of body after time t is :-

A ball is thrown at an angle theta with the horizontal and the range is maximum. The value of tantheta is:-

A particle is projected with a speed v and an angle theta to the horizontal. After a time t, the magnitude of the instantaneous velocity is equal to the magnitude of the average velocity from 0 to t. Find t.

A particle of mass m is projected with speed u at an angle theta with the horizontal. Find the torque of the weight of the particle about the point of projection when the particle is at the highest point.

If a projectile is fired at an angle theta with the vertical with velocity u, then maximum height attained is given by:-

A particle is projected horizontally with speed u from the top of a plane inclined at an angle theta with the horizontal. How far from the point of projection will the particle strike the plane?

The angle of projection at which the horizontal range and maximum height of projectile are equal is

A particle is projected with a velocity u making an angle theta with the horizontal. At any instant its velocity becomes v which is perpendicular to the initial velocity u. Then v is

A particle of mass m has been thrown with intial speed u making angle theta with the horizontal ground. Find the angular momentum of the projectile about an axis perpendicular to the plane and passing through the point of projection when the projectile is (a) At the highest point (b) About to hit the ground

A projectile fired with initial velocity u at some angle theta has a range R . If the initial velocity be doubled at the same angle of projection, then the range will be