Home
Class 11
PHYSICS
The position of a particle moving along ...

The position of a particle moving along `x-`axis varies with time `t` according as `x=sqrt3sinomegat-cosomegat` where `omega` is a constant. Find the region in which the particle is confined.

Text Solution

Verified by Experts

`:' x=sqrt(3) sin omegat-cos omegat`
`:. x_("max")=sqrt((sqrt(3))^(2)+(-1)^(2))=2` and `x_("min")=sqrt((sqrt(3))^(2)+(-1)^(2))=-2`
Thus, the particle is confined in the region `-2 le x le 2`
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS

    ALLEN |Exercise Part -II Example|61 Videos
  • MISCELLANEOUS

    ALLEN |Exercise Part -II Example Some worked out Examples|1 Videos
  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN |Exercise BEGINNER S BOX-7|8 Videos
  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN |Exercise EXERCISE-IV|7 Videos

Similar Questions

Explore conceptually related problems

The position of a particle moving along x-axis varies with time t according to equation x=sqrt(3) sinomegat-cosomegat where omega is constants. Find the region in which the particle is confined.

The position of a particle moving in space varies with time t according as :- x(t)=3 cosomegat y(t)=3sinomegat z(t)=3t-8 where omega is a constant. Minimum distance of particle from origin is :-

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

The displacement of a particle varies with time according to the relation y= a sin omega t+b cos omega t ……………

The position of a particle moving along x-axis varies eith time t as x=4t-t^(2)+1 . Find the time interval(s) during which the particle is moving along positive x-direction.

For a particle moving along x- axis, speed must be increasing for the following graph :

(a) The position of a particle moving along the x-axis depends on the time according to equation. x=(3t^(2)-t^(3)) m. At what time does the particle reaches its maximum x-position? (b) What is the displacement during the first 4s.

Acceleration of particle moving along the x-axis varies according to the law a=-2v , where a is in m//s^(2) and v is in m//s . At the instant t=0 , the particle passes the origin with a velocity of 2 m//s moving in the positive x-direction. (a) Find its velocity v as function of time t. (b) Find its position x as function of time t. (c) Find its velocity v as function of its position coordinates. (d) find the maximum distance it can go away from the origin. (e) Will it reach the above-mentioned maximum distance?

The velocity (v) of a particle of mass m moving along x-axis is given by v=alphasqrt(x) , where alpha is a constant. Find work done by force acting on particle during its motion from x=0 to x=2m :-

The position of a particle moving in XY-plane varies with time t as x=t, y=3t-5 . (i) What is the path traced by the particle? (ii) When does the particle cross-x-axis?