Home
Class 11
PHYSICS
A parallelogram ABCD is shown in figure....

A parallelogram ABCD is shown in figure.

`{:(,"Column I",,,"Column II"),((A),"Equation of side AB",,(P),2y+x=2),((B),"Equation of side BC",,(Q),2y-x=2),((C),"Equation of side CD",,(R),2y+x=-2),((D),"Equation of side DA",,(S),2y-x=-2),(,,,(T),y+2x=2):}`

Text Solution

Verified by Experts

For side AB : `m=(1-0)/(0-(-2))=1/2, c=1rArry=1/2x+1`
For side BC : `m=(2-0)/(0-1)=-2, c=1rArr y=-2x+1`
For side CD : `m=(0-(-1))/(2-0)=1/2, c=-1rArry=1/2x-1`
For side DA : `m=(-1-0)/(0-(-2))=-1/2, c=-1rArry=-1/2x-1`
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS

    ALLEN |Exercise Part -II Example|61 Videos

  • MISCELLANEOUS

    ALLEN |Exercise Part -II Example Some worked out Examples|1 Videos

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN |Exercise BEGINNER S BOX-7|8 Videos

  • PHYSICAL WORLD, UNITS AND DIMENSIONS & ERRORS IN MEASUREMENT

    ALLEN |Exercise EXERCISE-IV|7 Videos

Similar Questions

Explore conceptually related problems

For conservative of U w.r.t. x keeping y and z constant and so on. {:(,"Column-I",,,"Column-II"),((A),"For" U=x^(2) yz"," at (5, 0,0),,(P),F_(x)=0),((B),"For" U=x^(2)+yz at (5, 0, 0),,(Q),F_(y)=0),((C),"For" U=x^(2)(y+z) at (5, 0, 0),,(R),F_(z)=0),((D),"For" U=x^(2)y+z at (5, 0,0),,(S),U=0):}

The equation of the line through the intersection of the lines 2x - 3y=0 and 4x -5y =2 and {:("Column - I","Column - II"),("(i) through the point (2, 1) is","(a)" (2x - y =4)),("(ii) perpendicular to the line" x + 2y + 1 =0 "is" , "(b)" x+y -5 =0),("(iii) parallel to the line" 3x - 4y + 5=0 "is","(c)" x-y -1 =0),("(iv) equally inclined to the axis is","(d)" 3x-4y-1 =0):}

Solve the system of equations {:(2x+5y=1),(3x+2y=7):},

Obtain equation of circle in x^(2) + y^(2) - 2x - 2y + 1 = 0

Obtain equation of circle in x^(2) + y^(2) - x + y = 0

Equation at sides of rectangle are x=a, x=a', y=b and y=b' . Obtain equation of its diagonals.

The solution of the matrix equation of [{:(x^(2)),(y^(2)):}]-4[{:(2x),(y):}]=[{:(-7),(12):}]= ........

If y is a function of x then (d^2y)/(dx^2)+y \ dy/dx=0. If x is a function of y then the equation becomes

The equation of normal to 3x^(2)-y^(2)=8 at (2, -2) is ……..

For each graph given below, four linear equations are given. Out of these find the equation that represents the given graph. (i) Equations are (A) y = x (B) x + y = 0 (C) y = 2x (D) 2 + 3y = 7x (ii) Equations are (A) y = x + 2 (B) y = x - 2 (C) y = -x + 2 (D) x + 2y = 6