Consider the equation `(d)/(dt)(intvec(F).dvec(S))=A(vec(F).vec(rho))` where `vec(F)equiv` force, `vec(s)equiv` displacement, `tequiv` time and `vec(rho)=` momentum. The dimensional formula of `A` will be `:-`
Consider the equation `(d)/(dt)(intvec(F).dvec(S))=A(vec(F).vec(rho))` where `vec(F)equiv` force, `vec(s)equiv` displacement, `tequiv` time and `vec(rho)=` momentum. The dimensional formula of `A` will be `:-`
A
`M^(0)L^(0)T^(0)`
B
`ML^(0)T^(0)`
C
`M^(-1)L^(0)T^(0)`
D
`M^(0)L^(0)T^(-1)`
Text Solution
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The correct Answer is:
C
`[d/(dt)(int vec(F).dvec(S))]=[A(vec(F).vec(p))]rArr[(Fs)/t]=[AFp]rArr[A]=[s/(pt)]=(L)/(MLT^(-1)xxT)=M^(-1)`
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