In a new system (say TK system) of measurement, the fundamental quantities length, mass and time are measured in Akshay, Shahrukh and Aamir respectively.
`1` Akshay `=1 km`
`1` Shahrukh `=1` Quintal (100 kg)
`1` Aamir `=1` minute
`{:("Column I",,,"Column II"),((A) "One unit of acceleration in TK system.",,,(P) 5/18xx10^(-4) SI "unit"),((B) "One unit of kinetic energy in TK system",,,(Q) 5/18xx10^(-3) MKS "unit"),((C) "One unit of pressure in TK system",,,(R)5/18xx10^(0) MKS "unit"),((D) "One unit of work in TK system",,,(S) 5/18xx10^(4) MKS "unit"),(,,,(T) 5/18xx10^(5) SI "unit"):}`

Answer

`(A) rarr (R); (B) rarr (T); (C) rarr (P); (D) rarr (T)`

Explanation

For (A) : `:' ["Acceleration"]=[LT^(-2)] :.` unit of acceleration `=(1 km) (1 min)^(-2)=5/18 m//s^(2)`
For (B) : `:' ["Kinetic energy"]=[ML^(2)T^(-2)]`
`:.` Unit of kinetic energy `=(1 "Quintal") (1 km)^(2) (1 "min")^(-2)=5/18 10^(5) kgm^(2) s^(-2)`
For (C) : `:' ["Pressure"]=[ML^(-1) T^(-2)]`
`:.` Unit of pressure `=(1 "Quintal") (1 km)^(-1) (1 "min")^(-2)=5/18 10^(-4) kgm^(-1) s^(-2)`
for (D) : `:' ["Work"]=[ML^(2)T^(-2)]`
`:.` Unit of work`=(1 "Quintal") (1 km)^(2) (1 "min")^(-2)=5/18 10^(5) kgm^(2) s^(-2)`