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10^(12)alpha- particles (Nuclei of heliu...

`10^(12)alpha`- particles (Nuclei of helium) per second falls on a neutral sphere, calculate time in which sphere gets charged by `2mu C`.

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Number of `alpha`-particles falling in t second `=10^(12) t`
Charge on `alpha`-particle `=+ 2e`, So charge incident in time `t =(10^(12)t).(2e)`
`:'` Give charge is `2 mu C" " :. 2xx10^(-6)=(10^(12)t)/(1.6xx10^(-19))=6.25 s`
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