The two conducting spherical shells are joined by a conducting wire and cut after some time when charge stops flowing. Find out the charge on each sphere after that.

Explanation

After cutting the wire, the potential of both the shells is equal
Thus, potential of inner shell `V_("in")=(Kx)/(R)+(K(-2Q-x))/(2R)=(K(x-2Q))/(2R)`
and potential of outer shell `V_("out")=(Kx)/(2R)+(K(-2Q-x))/(2R)=(-KQ)/(R)`
As `V_("out")=V_("in")rArr (-KR)/(R)=(K(x-2Q))/(2R)rArr -2Q=x-2Q rArr x=0`
So charge on inner spherical shell `=0` and outer spherical shell `=-2 Q`