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The projection of vec(A) on vec(B) is :-...

The projection of `vec(A)` on `vec(B)` is :-

A

`vec(A).vec(B)`

B

`vec(A).hat(B)`

C

`vec(B).vec(A)`

D

`hat(A).hat(B)`

Text Solution

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The correct Answer is:
B
`:' vec(A). Vec(B)= AB cos theta`
`:.` Projection of `vec(A)` on `vec(B)=A cos theta=(vec(A).vec(B))/(B)=vec(A).hat(B)`
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